GRADE 7 · ALGEBRA

Equations and Inequalities

Learn how to find unknown values, decide whether a statement is true, and describe a whole set of possible answers. This lesson builds on simplifying expressions and solving two-step equations.

Estimated learning time: 25–35 minutes · Beginner to intermediate

Learning goals

1. Expressions, equations and inequalities

An expression is a mathematical phrase such as 3x + 5. It has no equals or comparison sign. An equation says that two expressions have the same value, using =. An inequality compares values that may not be equal.

SymbolMeaningExample
=is equal tox + 2 = 9
<is less thanx < 9
>is greater thanx > 9
≤is less than or equal tox ≤ 9
≥is greater than or equal tox ≥ 9

In an equation, a solution is a value that makes the two sides equal. In an inequality, a solution is any value that makes the comparison true. An inequality can therefore have many solutions.

2. Keep an equation balanced

Think of an equation as a balanced scale. Whatever operation you perform on one side, perform the same operation on the other side. Use inverse operations to isolate the variable:

Example A: solve 3x + 5 = 20

3x + 5 = 20

Subtract 5 from both sides: 3x = 15.

Divide both sides by 3: x = 5.

Check: 3(5) + 5 = 15 + 5 = 20. The solution is correct.

Example B: variable terms on both sides

5x + 4 = 2x + 19

Subtract 2x from both sides: 3x + 4 = 19.

Subtract 4: 3x = 15. Divide by 3: x = 5.

Check: left side = 5(5) + 4 = 29; right side = 2(5) + 19 = 29.

Example C: use the distributive property first

2(x + 3) = 18

Expand: 2x + 6 = 18. Subtract 6: 2x = 12. Divide by 2: x = 6.

Helpful order: expand brackets if needed, collect variable terms on one side, collect number terms on the other, then divide or multiply to isolate the variable. Keep both sides balanced at every step.

3. Solve inequalities

You can usually solve an inequality in the same way as an equation. There is one important rule: when you multiply or divide both sides by a negative number, reverse the inequality sign.

Example D: add or subtract

x + 4 > 10

Subtract 4 from both sides: x > 6.

Any number greater than 6 makes the statement true, such as 7, 8 or 10.

Example E: divide by a negative number

−2x < 8

Divide both sides by −2 and reverse < to >: x > −4.

Check with x = 0: −2(0) < 8 becomes 0 < 8, which is true.

Remember: adding or subtracting the same number does not reverse the sign. Multiplying or dividing by a positive number does not reverse it either. Only multiplying or dividing by a negative number reverses the inequality sign.

4. Show solutions on a number line

A number-line graph makes an inequality easier to see.

InequalityEndpointDirection
x > 3Open at 3Right
x ≥ 3Filled at 3Right
x < −2Open at −2Left
x ≤ −2Filled at −2Left

For example, x ≥ 3 includes 3 and every number greater than 3. The endpoint is part of the solution set.

5. Turn words into algebra

Read the statement carefully, identify the unknown, and decide whether it describes an exact value or a limit.

Example F: an equation word problem

Three identical notebooks and a £2 pen cost £17 altogether. Let n be the price of one notebook.

3n + 2 = 17

Subtract 2: 3n = 15. Divide by 3: n = £5.

Example G: an inequality word problem

A club needs at least 24 members. It already has 15. Let m be the number of additional members needed.

15 + m ≥ 24

Subtract 15: m ≥ 9. The club needs at least 9 more members.

Language clues: “is”, “equals” or “the same as” often indicate an equation. “More than”, “fewer than”, “at least” and “no more than” indicate inequalities. Translate the meaning, not just individual words.

6. Common mistakes to avoid

7. Practice questions

Try each question before reading its solution.

  1. Solve: 4x + 7 = 31.
    Show solution

    Subtract 7: 4x = 24. Divide by 4: x = 6.

  2. Solve: 6x − 5 = 3x + 10.
    Show solution

    Subtract 3x: 3x − 5 = 10. Add 5: 3x = 15. Therefore x = 5.

  3. Solve: 3(x − 2) = 21.
    Show solution

    Expand: 3x − 6 = 21. Add 6: 3x = 27. Therefore x = 9.

  4. Solve: x − 8 ≤ 4.
    Show solution

    Add 8 to both sides: x ≤ 12.

  5. Solve: 5x > −20.
    Show solution

    Divide by positive 5; the sign stays the same: x > −4.

  6. Solve: −3x ≥ 12.
    Show solution

    Divide by −3 and reverse ≥ to ≤: x ≤ −4.

  7. A taxi charges a £4 starting fee plus £2 per mile. The total is £18. How many miles were travelled?
    Show solution

    Let d be miles: 4 + 2d = 18. Subtract 4: 2d = 14. Divide by 2: d = 7 miles.

  8. You have £30 and want to buy notebooks costing £4 each. What is the greatest whole number n you can buy without spending more than £30?
    Show solution

    4n ≤ 30, so n ≤ 7.5. Since n must be a whole number, the greatest possible number is 7 notebooks.

8. Quick knowledge check

Choose one answer for each question, then select Check answers to see your score and explanations.

0 of 5 answered

1. What is the solution to 2x + 3 = 13?

2. Solve 4x + 2 = 2x + 12.

3. What happens to the inequality sign when you divide both sides by −2?

4. Which graph endpoint represents x ≥ 6?

5. Solve −3x < 12.

9. Printable worksheet

Use these questions for independent practice. Show each step and check your answers after attempting the worksheet.

Equations and inequalities — Grade 7

Name: __________________________ Date: ______________

  1. Solve 7x + 1 = 36.
  2. Solve 4x − 3 = 2x + 9.
  3. Solve 5(x + 2) = 35.
  4. Solve x + 6 > 11.
  5. Solve 2x ≤ 14.
  6. Solve −4x > 20.
  7. A number doubled and then increased by 9 gives 25. Find the number.
  8. A ride costs $6 per person. A group has a budget of no more than $42. Write and solve an inequality for the greatest whole number of people who can ride.

Answer key

  1. x = 5. Subtract 1, then divide by 7.
  2. x = 6. Subtract 2x, add 3, then divide by 2.
  3. x = 5. Divide by 5, subtract 2.
  4. x > 5.
  5. x ≤ 7.
  6. x < −5. Reverse the sign when dividing by −4.
  7. 2n + 9 = 25, so n = 8.
  8. 6p ≤ 42, so p ≤ 7. Greatest whole number: 7 people.